![]() ![]() ![]() I would like to thank Miplet for confirming the table above. The next table is for four-card stud with no jokers. The second table is for a fully wild card. The first table is for a partially wild card that can only be used to complete a straight, flush, straight flush, or royal flush, otherwise it must be used as an ace (same usage as in pai gow poker). ![]() The next two tables show the probabilities in 5-card stud with one wild card. begingroup octave The probability of getting a straight (in poker) is (10C1)(45)/(52C5) because there are 10 ways you can have 5 numbers in a row if Ace counts as both the first and last number, and the 5 cards can be any of the 4 suits. The following table shows the number of combinations if each card was dealt from a separate deck, which would be mathematically equivalent to an infinite number of decks. If you have a standard deck of 52 cards, what is the probability that out of a hand of 5 cards you get 4 aces First I found the total of ways for choosing 5 cards from 52 (52 C 5) 2,598,960 Then the of hands which has 4 aces is 48 (because the 5th card can be any of 48 other cards). ![]()
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